Interactive engineering guide · Updated July 30, 2026

Fixed Beam Calculator & Formulas

Calculate reactions, hogging support moments, positive span moment and deflection for a beam fixed at both ends, then trace every result through the SFD, BMD and elastic curve.

Fixed at both ends UDL + center point load Live SFD, BMD + deflection
Steel fixed beam clamped at both ends under a uniform load with labeled shear, bending moment and displacement diagrams
End restraint creates support moments Double curvature creates two inflection points

Interactive fixed beam calculator

Change the span, load, units and EI. The reactions, fixed-end moments, shear, signed bending and deflection update immediately; the continuation button opens the same model in the full solver.

Live beam, shear, moment & deflection

Updates live
Fixed beam diagramInteractive beam diagram loading.
Fixed beam — Full-span UDL
Bending M(x) Open full diagram →
Deflection y(x) Open full diagram →

Deflected shape is scaled for clarity.

Quick calculator

Fixed beam calculator

Support model
Fixed at both ends
Analysis
Statically indeterminate
Choose a load case
m
kN/m

Left reaction RA

View shear diagram →

Right reaction RB

View shear diagram →

Critical moment Mmax

View moment diagram →

Midspan deflection δmax

View deflection diagram →
Material and section stiffness E·I Used for deflection

Need a real load arrangement? Continue with these inputs, then add loads, move supports, choose a section and export full results.

Open this exact beam in the full calculator

Calculator use is free; no signup is required to run the model.

Quick answer

What is a fixed beam?

A fixed beam has both ends restrained against translation and rotation. It is also called a fixed-fixed beam, built-in beam, clamped beam or encastré beam. Because end rotation is prevented, the supports develop bending moments as well as force reactions.

Under ordinary downward gravity loading, the beam usually has negative (hogging) moment near both ends, positive (sagging) moment in the span, and points of contraflexure where the moment changes sign.

MA ≠ 0MB ≠ 0rotation restrainedrotation restrainedRARBHAHBMAMBspan L

Read the restraint before the formulas

Both ends fixed
The ideal supports prevent slope and vertical displacement at A and B.

End moments
Rotational restraint creates non-zero hogging moments at both supports.

Span response
The beam still bends between supports and normally develops positive moment near midspan.

Fixity is a stiffness assumption: a connection is not fixed merely because it is bolted, welded or cast into concrete. The connection, columns or walls, foundations and adjacent framing must provide enough rotational restraint for the fixed-end idealization.

From structure to model

Where fixed beams appear in real life

The fixed-fixed idealization is useful when both surrounding supports strongly restrain end rotation. Real joints have finite stiffness, so these examples are candidates for the model rather than proof of perfect fixity.

Concrete construction

Monolithic concrete frame beam

Idealized model
Rotation restrained at both beam–column joints.

Why it fits
A beam cast continuously with substantial columns can develop hogging moments at both joints and sagging moment in the span.
Model with care
Column and foundation flexibility redistribute moment. Analyze the full frame when joint rotation is important rather than assuming infinitely rigid ends.

Machines and test rigs

Clamped machine crossmember

Idealized model
Rigid clamp at each end of a short member.

Why it fits
Deep bolted or welded end blocks can suppress slope at both ends, creating the characteristic double-curvature response.
Model with care
Bolt slip, local plate flexibility, contact and vibration can dominate. The clamp stiffness should be checked against the member stiffness.

Steel buildings

Steel moment-frame girder

Idealized model
Moment-resisting connection at both beam–column joints.

Why it fits
Extended end plates, bolt groups and stiffened haunches can transfer end moment into the columns and strongly restrain beam-end rotation.
Model with care
Connection, panel-zone and column flexibility make the joints semi-rigid in practice. Use the verified connection stiffness when it materially affects the response.

Recognition rule: fixity is relative stiffness. A connection that looks rigid may still rotate enough to invalidate fixed-end coefficients, while a monolithic joint may be close to fixed for one check but not another.

Fixed beam formulas

Fixed-end moments, reactions and deflection

These closed-form cases assume a straight prismatic member, constant EI, level supports and perfect fixity at both ends. Positive moment is sagging; negative moment is hogging.

Load caseReactionsSupport momentsPositive span momentMaximum deflection
Full-span UDL w RA = RB = wL/2 MA = MB = −wL2/12 Mmid = +wL2/24 δmax = wL4/(384EI)
Point load P at midspan RA = RB = P/2 MA = MB = −PL/8 Mmid = +PL/8 δmax = PL3/(192EI)
P point load w force per length L fixed-to-fixed span E Young’s modulus I second moment of area EI flexural rigidity

Useful locations: for the UDL case, zero moment occurs at x = 0.2113L and 0.7887L. For a central point load, the inflection points are at L/4 and 3L/4. End slopes and end deflections are zero in both ideal cases.

Comparing support systems or looking for V(x), M(x), slope and elastic-curve equations? Use the complete beam deflection formula library.

Fixed beam SFD and BMD

How the load changes shear, moment and deflection

The support reactions can look deceptively similar to a simply supported beam, but the bending diagram is fundamentally different because both end rotations are restrained.

How to read the plots: positive shear and sagging moment are above their baselines; negative values are below. The dashed orange line is the exaggerated deflected shape.

w

Full-span UDL

UDL over full span

Constant load intensity w from fixed end A to fixed end B.

w kN/m over full spanRARBHAHBMAMBShear diagramVSHEARMoment diagramMMOMENTDeflection diagramδDEFLECTION|V|max = wL/2|Mend| = wL²/12Mmid = wL²/24δmax = wL⁴/(384EI)
  • Shear: linear from +wL/2 to −wL/2.
  • Moment: −wL²/12 at each end and +wL²/24 at midspan.
  • Deflection: symmetric, with wL⁴/(384EI) at midspan.
Open UDL fixed-beam model
P

Point load at midspan

P at midspan

Concentrated load P at the center of a fixed-fixed span.

P at midspanRARBHAHBMAMBShear diagramVSHEARMoment diagramMMOMENTDeflection diagramδDEFLECTION|V|max = P/2|Mend| = PL/8Mmid = PL/8δmax = PL³/(192EI)
  • Shear: +P/2 to the load, then −P/2.
  • Moment: equal-magnitude −PL/8 end moments and +PL/8 at the load.
  • Deflection: symmetric, with PL³/(192EI) at midspan.
Open point-load fixed-beam model

Worked calculations

Two complete fixed beam examples

Each example keeps the same model used by the interactive calculator so the arithmetic, diagrams and full-solver handoff can be checked against one another.

Example 1 · full-span UDL

6 m fixed beam with 10 kN/m UDL

Steel-like E = 200 GPa · I = 100 × 106 mm4

Open exact model
Model + response diagramsUDL over full span
w kN/m over full spanRARBHAHBMAMBShear diagramVSHEARMoment diagramMMOMENTDeflection diagramδDEFLECTION|V|max = wL/2|Mend| = wL²/12Mmid = wL²/24δmax = wL⁴/(384EI)
Vertical reactions: 30 kN each Fixed-end moments: −30 kN·m Positive midspan moment: +15 kN·m Maximum deflection: 1.69 mm
Span
L = 6 m
Uniform load
w = 10 kN/m
Elastic modulus
E = 200 GPa
Second moment of area
I = 100 × 106 mm4
Flexural stiffness
EI = 20,000 kN·m2

1 · Vertical reactions

RA = RB = wL/2 = 10(6)/230 kN each

2 · Fixed-end moments

MA = MB = −wL2/12−30 kN·m

3 · Positive midspan moment

Mmid = wL2/24+15 kN·m

4 · Maximum deflection

δmax = wL4/(384EI)1.69 mm

The support moment magnitude is twice the positive midspan moment. A strength check therefore needs both hogging and sagging regions, and reinforcement or lateral restraint may differ between them.

Example 2 · center point load

6 m fixed beam with a 30 kN center load

Same EI as Example 1 for a direct response comparison

Open exact model
Model + response diagramsPoint load at midspan
P at midspanRARBHAHBMAMBShear diagramVSHEARMoment diagramMMOMENTDeflection diagramδDEFLECTION|V|max = P/2|Mend| = PL/8Mmid = PL/8δmax = PL³/(192EI)
Vertical reactions: 15 kN each Fixed-end moments: −22.5 kN·m Moment under the load: +22.5 kN·m Maximum deflection: 1.69 mm
Span
L = 6 m
Point load
P = 30 kN
Elastic modulus
E = 200 GPa
Second moment of area
I = 100 × 106 mm4
Flexural stiffness
EI = 20,000 kN·m2

1 · Vertical reactions

RA = RB = P/2 = 30/215 kN each

2 · Fixed-end moments

MA = MB = −PL/8−22.5 kN·m

3 · Moment under the load

Mmid = +PL/8+22.5 kN·m

4 · Maximum deflection

δmax = PL3/(192EI)1.69 mm

For this symmetric point load, the hogging support moments and sagging midspan moment have the same magnitude. The bending diagram crosses zero at L/4 and 3L/4.

Practical fixed-end modeling

When is the fixed-fixed model appropriate?

Fixed beams appear in monolithic concrete frames, rigid moment frames, deep wall-to-wall members and some laboratory or machine components. The essential requirement is rotational restraint at both ends—not the material or connection label by itself.

Choose the closest behavior. Use a simply supported model when end rotation is effectively free; use a semi-rigid or frame model when columns and joints rotate; use a continuous beam model when the member passes over an interior support.

Good candidates

  • Monolithic beam–wall or beam–column joints with substantial rotational stiffness.
  • Members clamped into massive supports on both ends.
  • Symmetric textbook checks where support settlement is negligible.
  • Constant-EI members in linear-elastic, small-deflection response.

Use a different model when

  • Connections behave as pins or have meaningful semi-rigid rotation.
  • Supports settle, rotate or have unequal stiffness.
  • The member continues into adjacent spans.
  • Cracking, yielding, large deflection, shear deformation or changing EI materially affects response.

Five frequent calculation mistakes

  1. Assuming every rigid-looking joint is perfectly fixed. Connection and framing stiffness control the actual moment restraint.
  2. Reporting only the positive span moment. The negative support moments can be larger and reverse the tension face.
  3. Using simply supported deflection formulas. Rotational restraint changes both curvature and the coefficient.
  4. Ignoring contraflexure. Moment changes sign, which matters for reinforcement, bracing and interpretation.
  5. Mixing length units in EI. Convert E, I, load and span to one compatible unit system before calculating deflection.

Boundary-condition comparison

Fixed beam vs. simply supported beam

QuestionFixed-fixed beamSimply supported beam
End rotationRestrained at both endsAllowed at pin and roller
Support momentNormally non-zeroZero in the ideal model
UDL maximum moment|M| = wL²/12 at supportsM = wL²/8 at midspan
UDL maximum deflectionwL⁴/384EI5wL⁴/384EI
Analysis typeStatically indeterminateStatically determinate

For equal L, w and EI, the ideal fixed-fixed UDL deflection is one-fifth of the simply supported value. That advantage depends on the real end restraint being present and maintained.

Engineering basis

Assumptions and limits of the formulas

  • Beam theory: Euler–Bernoulli bending.
  • Geometry: straight, slender, prismatic member.
  • Supports: zero vertical displacement and zero rotation at both ends.
  • Material: homogeneous and linear elastic.
  • Response: static load and small deflection.
  • Not included: code design, connection stiffness, settlement, buckling or dynamics.

Closed-form coefficients were cross-checked against the American Wood Council Design Aid 6 fixed-at-both-ends cases and the live explorer equations. The guide is educational analysis, not project-specific design.

Engineering authorship

Prepared and reviewed by

Formula scope, boundary conditions, sign conventions, worked substitutions and modeling limitations were technically reviewed for the exact beam cases presented on this page. Last technical review: July 30, 2026.

Read engineering biography

Sources and verification

Reference basis and checking process

The equations are classical, closed-form Euler–Bernoulli beam solutions. Coefficients and boundary-condition behavior for the fixed-fixed center-point-load and full-span UDL cases were checked against the references below before the worked values were published.

How the examples were checked

Each expected value was recalculated from the displayed equation and checked against force and moment equilibrium where applicable. The worked-example links carry the same geometry, stiffness and loading into the calculator so the response diagrams can be compared with the hand check.

Review the published solver verification methodology

These checks verify the stated idealized analysis cases; they do not constitute design certification or replace project-specific review of loading, restraints, stability, connections and governing requirements.

Frequently asked questions

Fixed beam questions

What is a fixed beam?

A fixed beam, also called a fixed-fixed, built-in, clamped-clamped or encastré beam, has both ends restrained against translation and rotation in the ideal model.

What is the fixed beam deflection formula for a full-span UDL?

For a prismatic fixed-fixed beam with uniform load w across span L, the maximum deflection is wL^4/(384EI) at midspan.

What are the fixed-end moments for a UDL?

The support moments are equal hogging moments, MA = MB = -wL^2/12, while the positive midspan moment is +wL^2/24.

What are the fixed-end moments for a center point load?

A central point load P gives MA = MB = -PL/8 and a positive midspan moment of +PL/8. Each vertical reaction is P/2.

Where are the points of contraflexure in a fixed beam under UDL?

For a full-span UDL, zero moment occurs at approximately 0.2113L and 0.7887L from the left end.

Is a real beam connection perfectly fixed?

Rarely. A connection may be treated as fixed only when its rotational stiffness and the surrounding frame justify that idealization for the analysis objective.

Is a fixed beam statically determinate?

No. A fixed-fixed beam is statically indeterminate, so equilibrium alone cannot determine all reactions; deformation compatibility and stiffness are also required.

When should I use the full beam calculator?

Use it for partial or multiple loads, off-center point loads, applied moments, varying EI, settlements, semi-rigid behavior or when you need full diagrams and report-ready results.

Continue the analysis

Model the actual fixed beam, not just a symmetric textbook case.

Move loads away from midspan, add partial distributed loads or moments, change sections, inspect every diagram and export the complete analysis in the full calculator.

Open fixed beam in calculator →